Base | Representation |
---|---|
bin | 10010111110011110011… |
… | …000100110100101010001 |
3 | 11121122221020220120020101 |
4 | 102332132120212211101 |
5 | 132331124234342210 |
6 | 2435021510412401 |
7 | 163133065001512 |
oct | 22763630464521 |
9 | 4548836816211 |
10 | 1304032340305 |
11 | 463045295142 |
12 | 190891961101 |
13 | 95c7b630116 |
14 | 47188d1aa09 |
15 | 23dc2e37a3a |
hex | 12f9e626951 |
1304032340305 has 16 divisors (see below), whose sum is σ = 1570797897984. Its totient is φ = 1039254053760.
The previous prime is 1304032340293. The next prime is 1304032340309. The reversal of 1304032340305 is 5030432304031.
It is not a de Polignac number, because 1304032340305 - 215 = 1304032307537 is a prime.
It is a super-3 number, since 3×13040323403053 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1304032340309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12491254 + ... + 12595216.
It is an arithmetic number, because the mean of its divisors is an integer number (98174868624).
Almost surely, 21304032340305 is an apocalyptic number.
It is an amenable number.
1304032340305 is a deficient number, since it is larger than the sum of its proper divisors (266765557679).
1304032340305 is a wasteful number, since it uses less digits than its factorization.
1304032340305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 113496.
The product of its (nonzero) digits is 12960, while the sum is 28.
Adding to 1304032340305 its reverse (5030432304031), we get a palindrome (6334464644336).
The spelling of 1304032340305 in words is "one trillion, three hundred four billion, thirty-two million, three hundred forty thousand, three hundred five".
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