Base | Representation |
---|---|
bin | 1011110111000011000010… |
… | …0010011110011001011001 |
3 | 1201011122101101000121001010 |
4 | 2331300300202132121121 |
5 | 3202123101233220200 |
6 | 43422351444444133 |
7 | 2514063442041300 |
oct | 275606042363131 |
9 | 51148341017033 |
10 | 13040335054425 |
11 | 41784141a5118 |
12 | 15673799a9649 |
13 | 737910290223 |
14 | 331226ccd437 |
15 | 1793207a4150 |
hex | bdc3089e659 |
13040335054425 has 36 divisors (see below), whose sum is σ = 25080023997456. Its totient is φ = 5961296023200.
The previous prime is 13040335054393. The next prime is 13040335054441. The reversal of 13040335054425 is 52445053304031.
13040335054425 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13040335054425 - 25 = 13040335054393 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1774191571 + ... + 1774198920.
Almost surely, 213040335054425 is an apocalyptic number.
13040335054425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13040335054425 is a deficient number, since it is larger than the sum of its proper divisors (12039688943031).
13040335054425 is a wasteful number, since it uses less digits than its factorization.
13040335054425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3548390518 (or 3548390506 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 39.
Adding to 13040335054425 its reverse (52445053304031), we get a palindrome (65485388358456).
The spelling of 13040335054425 in words is "thirteen trillion, forty billion, three hundred thirty-five million, fifty-four thousand, four hundred twenty-five".
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