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13040335105 = 57617603859
BaseRepresentation
bin11000010010100001…
…11011100100000001
31020122210200122211021
430021100323210001
5203201311210410
65553551345441
7641103006460
oct141120734401
936583618737
1013040335105
115591a24856
12263b222281
1312ca854c25
148b9c689d7
15514c6ceda
hex30943b901

13040335105 has 16 divisors (see below), whose sum is σ = 17912903040. Its totient is φ = 8927436672.

The previous prime is 13040335081. The next prime is 13040335117. The reversal of 13040335105 is 50153304031.

It is not a de Polignac number, because 13040335105 - 213 = 13040326913 is a prime.

It is a super-2 number, since 2×130403351052 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13040335105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 280335 + ... + 323524.

It is an arithmetic number, because the mean of its divisors is an integer number (1119556440).

Almost surely, 213040335105 is an apocalyptic number.

It is an amenable number.

13040335105 is a deficient number, since it is larger than the sum of its proper divisors (4872567935).

13040335105 is an equidigital number, since it uses as much as digits as its factorization.

13040335105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 604488.

The product of its (nonzero) digits is 2700, while the sum is 25.

Adding to 13040335105 its reverse (50153304031), we get a palindrome (63193639136).

The spelling of 13040335105 in words is "thirteen billion, forty million, three hundred thirty-five thousand, one hundred five".

Divisors: 1 5 7 35 617 3085 4319 21595 603859 3019295 4227013 21135065 372581003 1862905015 2608067021 13040335105