130403445321543 has 4 divisors (see below), whose sum is σ = 173871260428728. Its totient is φ = 86935630214360.

The previous prime is 130403445321511. The next prime is 130403445321619. The reversal of 130403445321543 is 345123544304031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130403445321543 - 2⁵ = 130403445321511 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130403445321495 and 130403445321504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130403445321043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21733907553588 + ... + 21733907553593.

It is an arithmetic number, because the mean of its divisors is an integer number (43467815107182).

Almost surely, 2^{130403445321543} is an apocalyptic number.

130403445321543 is a deficient number, since it is larger than the sum of its proper divisors (43467815107185).

130403445321543 is an equidigital number, since it uses as much as digits as its factorization.

130403445321543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43467815107184.

The product of its (nonzero) digits is 1036800, while the sum is 42.

Adding to 130403445321543 its reverse (345123544304031), we get a palindrome (475526989625574).

The spelling of 130403445321543 in words is "one hundred thirty trillion, four hundred three billion, four hundred forty-five million, three hundred twenty-one thousand, five hundred forty-three".