13040401000025 has 72 divisors (see below), whose sum is σ = 19101094808832. Its totient is φ = 8650990944000.

The previous prime is 13040401000019. The next prime is 13040401000061. The reversal of 13040401000025 is 52000010404031.

13040401000025 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13040401000025 - 2⁴ = 13040401000009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13040400999970 and 13040401000006.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 698421440 + ... + 698440110.

It is an arithmetic number, because the mean of its divisors is an integer number (265292983456).

Almost surely, 2^{13040401000025} is an apocalyptic number.

It is an amenable number.

13040401000025 is a deficient number, since it is larger than the sum of its proper divisors (6060693808807).

13040401000025 is a wasteful number, since it uses less digits than its factorization.

13040401000025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22903 (or 22867 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 20.

Adding to 13040401000025 its reverse (52000010404031), we get a palindrome (65040411404056).

The spelling of 13040401000025 in words is "thirteen trillion, forty billion, four hundred one million, twenty-five", and thus it is an aban number.