130404331103 has 4 divisors (see below), whose sum is σ = 130405728600. Its totient is φ = 130402933608.

The previous prime is 130404331069. The next prime is 130404331129. The reversal of 130404331103 is 301133404031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130404331103 - 2¹² = 130404327007 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130404231103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547928 + ... + 749021.

It is an arithmetic number, because the mean of its divisors is an integer number (32601432150).

Almost surely, 2^130404331103 is an apocalyptic number.

130404331103 is a deficient number, since it is larger than the sum of its proper divisors (1397497).

130404331103 is a wasteful number, since it uses less digits than its factorization.

130404331103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1397496.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 130404331103 its reverse (301133404031), we get a palindrome (431537735134).

The spelling of 130404331103 in words is "one hundred thirty billion, four hundred four million, three hundred thirty-one thousand, one hundred three".