Base | Representation |
---|---|
bin | 1011110111000011011011… |
… | …0111000011001001100111 |
3 | 1201011122122202120211111201 |
4 | 2331300312313003021213 |
5 | 3202123310411024033 |
6 | 43422410153543331 |
7 | 2514066200360455 |
oct | 275606667031147 |
9 | 51148582524451 |
10 | 13040441111143 |
11 | 41784690530a6 |
12 | 15673a9414b47 |
13 | 737929244794 |
14 | 3312370199d5 |
15 | 179329c5347d |
hex | bdc36dc3267 |
13040441111143 has 4 divisors (see below), whose sum is σ = 13062139017088. Its totient is φ = 13018743205200.
The previous prime is 13040441111059. The next prime is 13040441111183. The reversal of 13040441111143 is 34111114404031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13040441111143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13040441111183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10848952071 + ... + 10848953272.
It is an arithmetic number, because the mean of its divisors is an integer number (3265534754272).
Almost surely, 213040441111143 is an apocalyptic number.
13040441111143 is a deficient number, since it is larger than the sum of its proper divisors (21697905945).
13040441111143 is an equidigital number, since it uses as much as digits as its factorization.
13040441111143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21697905944.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 13040441111143 its reverse (34111114404031), we get a palindrome (47151555515174).
The spelling of 13040441111143 in words is "thirteen trillion, forty billion, four hundred forty-one million, one hundred eleven thousand, one hundred forty-three".
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