Base | Representation |
---|---|
bin | 1011110111000011011100… |
… | …0011010000001110010111 |
3 | 1201011122122222121101002120 |
4 | 2331300313003100032113 |
5 | 3202123312220413143 |
6 | 43422410350311023 |
7 | 2514066236514015 |
oct | 275606703201627 |
9 | 51148588541076 |
10 | 13040444310423 |
11 | 417846a938832 |
12 | 15673aa4b8473 |
13 | 737929ac4a4a |
14 | 33123760d8b5 |
15 | 17932a186383 |
hex | bdc370d0397 |
13040444310423 has 16 divisors (see below), whose sum is σ = 17556955243776. Its totient is φ = 8608789995840.
The previous prime is 13040444310367. The next prime is 13040444310437. The reversal of 13040444310423 is 32401344404031.
It is not a de Polignac number, because 13040444310423 - 212 = 13040444306327 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13040444311423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5110836 + ... + 7225062.
It is an arithmetic number, because the mean of its divisors is an integer number (1097309702736).
Almost surely, 213040444310423 is an apocalyptic number.
13040444310423 is a deficient number, since it is larger than the sum of its proper divisors (4516510933353).
13040444310423 is a wasteful number, since it uses less digits than its factorization.
13040444310423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2134294.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 13040444310423 its reverse (32401344404031), we get a palindrome (45441788714454).
The spelling of 13040444310423 in words is "thirteen trillion, forty billion, four hundred forty-four million, three hundred ten thousand, four hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •