130405235 has 4 divisors (see below), whose sum is σ = 156486288. Its totient is φ = 104324184.

The previous prime is 130405211. The next prime is 130405243. The reversal of 130405235 is 532504031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 532504031 = 47 ⋅11329873.

It is a cyclic number.

It is not a de Polignac number, because 130405235 - 2⁸ = 130404979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130405235.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13040519 + ... + 13040528.

It is an arithmetic number, because the mean of its divisors is an integer number (39121572).

Almost surely, 2^130405235 is an apocalyptic number.

130405235 is a deficient number, since it is larger than the sum of its proper divisors (26081053).

130405235 is an equidigital number, since it uses as much as digits as its factorization.

130405235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26081052.

The product of its (nonzero) digits is 1800, while the sum is 23.

The square root of 130405235 is about 11419.5111541607. The cubic root of 130405235 is about 507.1055247077.

Adding to 130405235 its reverse (532504031), we get a palindrome (662909266).

The spelling of 130405235 in words is "one hundred thirty million, four hundred five thousand, two hundred thirty-five".