13040953 has 4 divisors (see below), whose sum is σ = 13052160. Its totient is φ = 13029748.

The previous prime is 13040917. The next prime is 13040957. The reversal of 13040953 is 35904031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 35904031 = 1171 ⋅30661.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13040953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13040957) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3625 + ... + 6262.

It is an arithmetic number, because the mean of its divisors is an integer number (3263040).

Almost surely, 2^13040953 is an apocalyptic number.

It is an amenable number.

13040953 is a deficient number, since it is larger than the sum of its proper divisors (11207).

13040953 is an equidigital number, since it uses as much as digits as its factorization.

13040953 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11206.

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 13040953 is about 3611.2259691135. The cubic root of 13040953 is about 235.3801181817.

Adding to 13040953 its reverse (35904031), we get a palindrome (48944984).

The spelling of 13040953 in words is "thirteen million, forty thousand, nine hundred fifty-three".