Base | Representation |
---|---|
bin | 10010111110100010011… |
… | …011001010011010110010 |
3 | 11121200002222110010211102 |
4 | 102332202123022122302 |
5 | 132331244112321432 |
6 | 2435032331244402 |
7 | 163134550060613 |
oct | 22764233123262 |
9 | 4550088403742 |
10 | 1304100120242 |
11 | 46307a57a217 |
12 | 1908b05a9702 |
13 | 95c8c6a22aa |
14 | 47193d21c0a |
15 | 23dc8d75962 |
hex | 12fa26ca6b2 |
1304100120242 has 4 divisors (see below), whose sum is σ = 1956150180366. Its totient is φ = 652050060120.
The previous prime is 1304100120143. The next prime is 1304100120331. The reversal of 1304100120242 is 2420210014031.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 880480078921 + 423620041321 = 938339^2 + 650861^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 326025030059 + ... + 326025030062.
Almost surely, 21304100120242 is an apocalyptic number.
1304100120242 is a deficient number, since it is larger than the sum of its proper divisors (652050060124).
1304100120242 is an equidigital number, since it uses as much as digits as its factorization.
1304100120242 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 652050060123.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 1304100120242 its reverse (2420210014031), we get a palindrome (3724310134273).
The spelling of 1304100120242 in words is "one trillion, three hundred four billion, one hundred million, one hundred twenty thousand, two hundred forty-two".
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