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1304104442021 = 5946147946779
BaseRepresentation
bin10010111110100010101…
…011101001100010100101
311121200010021120201012022
4102332202223221202211
5132331301214121041
62435033004032525
7163134631600553
oct22764253514245
94550107521168
101304104442021
11463081a61237
121908b1b32745
1395c90556464
1447194728bd3
1523dc942b24b
hex12fa2ae98a5

1304104442021 has 8 divisors (see below), whose sum is σ = 1329084741600. Its totient is φ = 1279220037040.

The previous prime is 1304104441999. The next prime is 1304104442029. The reversal of 1304104442021 is 1202444014031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304104442021 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304104442029) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23946191 + ... + 24000588.

It is an arithmetic number, because the mean of its divisors is an integer number (166135592700).

Almost surely, 21304104442021 is an apocalyptic number.

It is an amenable number.

1304104442021 is a deficient number, since it is larger than the sum of its proper divisors (24980299579).

1304104442021 is an equidigital number, since it uses as much as digits as its factorization.

1304104442021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47947299.

The product of its (nonzero) digits is 3072, while the sum is 26.

Adding to 1304104442021 its reverse (1202444014031), we get a palindrome (2506548456052).

The spelling of 1304104442021 in words is "one trillion, three hundred four billion, one hundred four million, four hundred forty-two thousand, twenty-one".

Divisors: 1 59 461 27199 47946779 2828859961 22103465119 1304104442021