Base | Representation |
---|---|
bin | 1011110111000101111101… |
… | …1001110000111100001001 |
3 | 1201011201102011111000112020 |
4 | 2331301133121300330021 |
5 | 3202131204023101413 |
6 | 43423001452435053 |
7 | 2514122100031155 |
oct | 275613731607411 |
9 | 51151364430466 |
10 | 13041121300233 |
11 | 4178787aa1244 |
12 | 1567559178a89 |
13 | 737a07138830 |
14 | 33129d4b8065 |
15 | 179369810c23 |
hex | bdc5f670f09 |
13041121300233 has 8 divisors (see below), whose sum is σ = 18725712636288. Its totient is φ = 8025305415504.
The previous prime is 13041121300223. The next prime is 13041121300241. The reversal of 13041121300233 is 33200312114031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13041121300233 - 25 = 13041121300201 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13041121300213) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 167193862785 + ... + 167193862862.
It is an arithmetic number, because the mean of its divisors is an integer number (2340714079536).
Almost surely, 213041121300233 is an apocalyptic number.
13041121300233 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13041121300233 is a deficient number, since it is larger than the sum of its proper divisors (5684591336055).
13041121300233 is a wasteful number, since it uses less digits than its factorization.
13041121300233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 334387725663.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 13041121300233 its reverse (33200312114031), we get a palindrome (46241433414264).
The spelling of 13041121300233 in words is "thirteen trillion, forty-one billion, one hundred twenty-one million, three hundred thousand, two hundred thirty-three".
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