Base | Representation |
---|---|
bin | 11000010010101001… |
… | …11111100100110010 |
3 | 1020122212200202202001 |
4 | 30021110333210302 |
5 | 203202044300424 |
6 | 5554030244214 |
7 | 641115033451 |
oct | 141124774462 |
9 | 36585622661 |
10 | 13041400114 |
11 | 5592591a26 |
12 | 263b65666a |
13 | 12cab38902 |
14 | 8ba064b98 |
15 | 514dcd844 |
hex | 30953f932 |
13041400114 has 8 divisors (see below), whose sum is σ = 19628865900. Its totient is φ = 6498444816.
The previous prime is 13041400081. The next prime is 13041400117. The reversal of 13041400114 is 41100414031.
13041400114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 12957951889 + 83448225 = 113833^2 + 9135^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13041400091 and 13041400100.
It is not an unprimeable number, because it can be changed into a prime (13041400117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11126889 + ... + 11128060.
Almost surely, 213041400114 is an apocalyptic number.
13041400114 is a deficient number, since it is larger than the sum of its proper divisors (6587465786).
13041400114 is a wasteful number, since it uses less digits than its factorization.
13041400114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22255244.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 13041400114 its reverse (41100414031), we get a palindrome (54141814145).
The spelling of 13041400114 in words is "thirteen billion, forty-one million, four hundred thousand, one hundred fourteen".
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