13041433151 has 4 divisors (see below), whose sum is σ = 13093391304. Its totient is φ = 12989475000.

The previous prime is 13041433133. The next prime is 13041433187. The reversal of 13041433151 is 15133414031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15133414031 = 47699 ⋅317269.

It is a cyclic number.

It is not a de Polignac number, because 13041433151 - 2³⁰ = 11967691327 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13041433151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13041433051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25978700 + ... + 25979201.

It is an arithmetic number, because the mean of its divisors is an integer number (3273347826).

Almost surely, 2^13041433151 is an apocalyptic number.

13041433151 is a deficient number, since it is larger than the sum of its proper divisors (51958153).

13041433151 is an equidigital number, since it uses as much as digits as its factorization.

13041433151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51958152.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 13041433151 its reverse (15133414031), we get a palindrome (28174847182).

The spelling of 13041433151 in words is "thirteen billion, forty-one million, four hundred thirty-three thousand, one hundred fifty-one".