13041440243333 has 4 divisors (see below), whose sum is σ = 13491145079340. Its totient is φ = 12591735407328.

The previous prime is 13041440243297. The next prime is 13041440243339. The reversal of 13041440243333 is 33334204414031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10198972377889 + 2842467865444 = 3193583^2 + 1685962^2 .

It is a cyclic number.

It is not a de Polignac number, because 13041440243333 - 2¹⁶ = 13041440177797 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13041440243293 and 13041440243302.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13041440243339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224852417960 + ... + 224852418017.

It is an arithmetic number, because the mean of its divisors is an integer number (3372786269835).

Almost surely, 2^{13041440243333} is an apocalyptic number.

It is an amenable number.

13041440243333 is a deficient number, since it is larger than the sum of its proper divisors (449704836007).

13041440243333 is an equidigital number, since it uses as much as digits as its factorization.

13041440243333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 449704836006.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 13041440243333 its reverse (33334204414031), we get a palindrome (46375644657364).

The spelling of 13041440243333 in words is "thirteen trillion, forty-one billion, four hundred forty million, two hundred forty-three thousand, three hundred thirty-three".