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130420140431 = 728533120323
BaseRepresentation
bin111100101110110100…
…1010110100110001111
3110110122012111120221112
41321131221112212033
54114100023443211
6135525244122235
712264634621400
oct1713551264617
9413565446845
10130420140431
1150346850929
122133953637b
13c3b5c48439
1464531d39a7
1535d4ba488b
hex1e5da5698f

130420140431 has 12 divisors (see below), whose sum is σ = 151891131672. Its totient is φ = 111657602448.

The previous prime is 130420140407. The next prime is 130420140511. The reversal of 130420140431 is 134041024031.

It is not a de Polignac number, because 130420140431 - 214 = 130420124047 is a prime.

It is a super-2 number, since 2×1304201404312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130420140397 and 130420140406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130420140131) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1518365 + ... + 1601958.

It is an arithmetic number, because the mean of its divisors is an integer number (12657594306).

Almost surely, 2130420140431 is an apocalyptic number.

130420140431 is a deficient number, since it is larger than the sum of its proper divisors (21470991241).

130420140431 is an equidigital number, since it uses as much as digits as its factorization.

130420140431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3121190 (or 3121183 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130420140431 its reverse (134041024031), we get a palindrome (264461164462).

The spelling of 130420140431 in words is "one hundred thirty billion, four hundred twenty million, one hundred forty thousand, four hundred thirty-one".

Divisors: 1 7 49 853 5971 41797 3120323 21842261 152895827 2661635519 18631448633 130420140431