Search a number
-
+
13042132035 = 353723499337
BaseRepresentation
bin11000010010101111…
…10010010001000011
31020122221001221202020
430021113302101003
5203202241211120
65554054052523
7641124202362
oct141127622103
936587057666
1013042132035
115592a41919
12263b94a143
1312cb033aba
148ba1b57d9
15514ec5640
hex3095f2443

13042132035 has 16 divisors (see below), whose sum is σ = 21431396256. Its totient is φ = 6767808768.

The previous prime is 13042132027. The next prime is 13042132049. The reversal of 13042132035 is 53023124031.

It is not a de Polignac number, because 13042132035 - 23 = 13042132027 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13042131996 and 13042132014.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11749114 + ... + 11750223.

It is an arithmetic number, because the mean of its divisors is an integer number (1339462266).

Almost surely, 213042132035 is an apocalyptic number.

13042132035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13042132035 is a deficient number, since it is larger than the sum of its proper divisors (8389264221).

13042132035 is a wasteful number, since it uses less digits than its factorization.

13042132035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23499382.

The product of its (nonzero) digits is 2160, while the sum is 24.

Adding to 13042132035 its reverse (53023124031), we get a palindrome (66065256066).

The spelling of 13042132035 in words is "thirteen billion, forty-two million, one hundred thirty-two thousand, thirty-five".

Divisors: 1 3 5 15 37 111 185 555 23499337 70498011 117496685 352490055 869475469 2608426407 4347377345 13042132035