Base | Representation |
---|---|
bin | 10010111110101001100… |
… | …100111001011010010111 |
3 | 11121200102100020101022102 |
4 | 102332221210321122113 |
5 | 132332020322100120 |
6 | 2435052255152315 |
7 | 163140535020434 |
oct | 22765144713227 |
9 | 4550370211272 |
10 | 1304220112535 |
11 | 4631312861aa |
12 | 19092481569b |
13 | 95cab4c5852 |
14 | 471a5c38b8b |
15 | 23dd4678d75 |
hex | 12fa9939697 |
1304220112535 has 16 divisors (see below), whose sum is σ = 1577511936000. Its totient is φ = 1035078853536.
The previous prime is 1304220112529. The next prime is 1304220112537. The reversal of 1304220112535 is 5352110224031.
It is a cyclic number.
It is not a de Polignac number, because 1304220112535 - 24 = 1304220112519 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1304220112498 and 1304220112507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304220112537) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8726366 + ... + 8874564.
It is an arithmetic number, because the mean of its divisors is an integer number (98594496000).
Almost surely, 21304220112535 is an apocalyptic number.
1304220112535 is a deficient number, since it is larger than the sum of its proper divisors (273291823465).
1304220112535 is a wasteful number, since it uses less digits than its factorization.
1304220112535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 162190.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 1304220112535 its reverse (5352110224031), we get a palindrome (6656330336566).
The spelling of 1304220112535 in words is "one trillion, three hundred four billion, two hundred twenty million, one hundred twelve thousand, five hundred thirty-five".
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