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13042411403 = 76149961211
BaseRepresentation
bin11000010010110001…
…10110011110001011
31020122221121010222012
430021120312132023
5203202324131103
65554104050135
7641126445020
oct141130663613
936587533865
1013042411403
1155931127aa
12263ba6394b
1312cb100cc8
148ba249547
1551502d2d8
hex30963678b

13042411403 has 16 divisors (see below), whose sum is σ = 15180576000. Its totient is φ = 10973728800.

The previous prime is 13042411391. The next prime is 13042411409. The reversal of 13042411403 is 30411424031.

13042411403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13042411403 - 210 = 13042410379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13042411409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182468 + ... + 243678.

It is an arithmetic number, because the mean of its divisors is an integer number (948786000).

Almost surely, 213042411403 is an apocalyptic number.

13042411403 is a deficient number, since it is larger than the sum of its proper divisors (2138164597).

13042411403 is an equidigital number, since it uses as much as digits as its factorization.

13042411403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61778.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13042411403 its reverse (30411424031), we get a palindrome (43453835434).

The spelling of 13042411403 in words is "thirteen billion, forty-two million, four hundred eleven thousand, four hundred three".

Divisors: 1 7 61 427 499 3493 30439 61211 213073 428477 3733871 26137097 30544289 213810023 1863201629 13042411403