Base | Representation |
---|---|
bin | 11000010010110001… |
… | …10110011110001011 |
3 | 1020122221121010222012 |
4 | 30021120312132023 |
5 | 203202324131103 |
6 | 5554104050135 |
7 | 641126445020 |
oct | 141130663613 |
9 | 36587533865 |
10 | 13042411403 |
11 | 55931127aa |
12 | 263ba6394b |
13 | 12cb100cc8 |
14 | 8ba249547 |
15 | 51502d2d8 |
hex | 30963678b |
13042411403 has 16 divisors (see below), whose sum is σ = 15180576000. Its totient is φ = 10973728800.
The previous prime is 13042411391. The next prime is 13042411409. The reversal of 13042411403 is 30411424031.
13042411403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 13042411403 - 210 = 13042410379 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13042411409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 182468 + ... + 243678.
It is an arithmetic number, because the mean of its divisors is an integer number (948786000).
Almost surely, 213042411403 is an apocalyptic number.
13042411403 is a deficient number, since it is larger than the sum of its proper divisors (2138164597).
13042411403 is an equidigital number, since it uses as much as digits as its factorization.
13042411403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61778.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13042411403 its reverse (30411424031), we get a palindrome (43453835434).
The spelling of 13042411403 in words is "thirteen billion, forty-two million, four hundred eleven thousand, four hundred three".
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