1304242541345 has 4 divisors (see below), whose sum is σ = 1565091049620. Its totient is φ = 1043394033072.

The previous prime is 1304242541341. The next prime is 1304242541351. The reversal of 1304242541345 is 5431452424031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 810403250176 + 493839291169 = 900224^2 + 702737^2 .

It is a cyclic number.

It is not a de Polignac number, because 1304242541345 - 2² = 1304242541341 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1304242541299 and 1304242541308.

It is not an unprimeable number, because it can be changed into a prime (1304242541341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130424254130 + ... + 130424254139.

It is an arithmetic number, because the mean of its divisors is an integer number (391272762405).

Almost surely, 2^{1304242541345} is an apocalyptic number.

It is an amenable number.

1304242541345 is a deficient number, since it is larger than the sum of its proper divisors (260848508275).

1304242541345 is an equidigital number, since it uses as much as digits as its factorization.

1304242541345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 260848508274.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 1304242541345 its reverse (5431452424031), we get a palindrome (6735694965376).

The spelling of 1304242541345 in words is "one trillion, three hundred four billion, two hundred forty-two million, five hundred forty-one thousand, three hundred forty-five".