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1304251352023 = 10112913379723
BaseRepresentation
bin10010111110101011011…
…100000100001111010111
311121200111112000111211111
4102332223130010033113
5132332101321231043
62435055332515451
7163141364400604
oct22765334041727
94550445014744
101304251352023
11463147982964
1219093317bb87
1395cb4b12a59
14471aa04b6ab
1523dd729a09d
hex12fab7043d7

1304251352023 has 4 divisors (see below), whose sum is σ = 1317164731848. Its totient is φ = 1291337972200.

The previous prime is 1304251351969. The next prime is 1304251352087. The reversal of 1304251352023 is 3202531524031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1304251352023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304251352093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6456689761 + ... + 6456689962.

It is an arithmetic number, because the mean of its divisors is an integer number (329291182962).

Almost surely, 21304251352023 is an apocalyptic number.

1304251352023 is a deficient number, since it is larger than the sum of its proper divisors (12913379825).

1304251352023 is a wasteful number, since it uses less digits than its factorization.

1304251352023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12913379824.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 1304251352023 its reverse (3202531524031), we get a palindrome (4506782876054).

The spelling of 1304251352023 in words is "one trillion, three hundred four billion, two hundred fifty-one million, three hundred fifty-two thousand, twenty-three".

Divisors: 1 101 12913379723 1304251352023