Base | Representation |
---|---|
bin | 11000010010110011… |
… | …10110000010000001 |
3 | 1020122222002101002111 |
4 | 30021121312002001 |
5 | 203202410443440 |
6 | 5554113415321 |
7 | 641131611025 |
oct | 141131660201 |
9 | 36588071074 |
10 | 13042671745 |
11 | 5593280364 |
12 | 263bb6a541 |
13 | 12cb19265c |
14 | 8ba2b6385 |
15 | 5150804ea |
hex | 309676081 |
13042671745 has 32 divisors (see below), whose sum is σ = 16993670400. Its totient is φ = 9570908160.
The previous prime is 13042671727. The next prime is 13042671749. The reversal of 13042671745 is 54717624031.
It is not a de Polignac number, because 13042671745 - 211 = 13042669697 is a prime.
It is a super-2 number, since 2×130426717452 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13042671698 and 13042671707.
It is not an unprimeable number, because it can be changed into a prime (13042671749) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6212706 + ... + 6214804.
It is an arithmetic number, because the mean of its divisors is an integer number (531052200).
Almost surely, 213042671745 is an apocalyptic number.
It is an amenable number.
13042671745 is a deficient number, since it is larger than the sum of its proper divisors (3950998655).
13042671745 is a wasteful number, since it uses less digits than its factorization.
13042671745 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3945.
The product of its (nonzero) digits is 141120, while the sum is 40.
The spelling of 13042671745 in words is "thirteen billion, forty-two million, six hundred seventy-one thousand, seven hundred forty-five".
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