Base | Representation |
---|---|
bin | 11000010010110100… |
… | …10000000000000001 |
3 | 1020122222021210000001 |
4 | 30021122100000001 |
5 | 203202422344423 |
6 | 5554120000001 |
7 | 641132533111 |
oct | 141132200001 |
9 | 36588253001 |
10 | 13042778113 |
11 | 5593343272 |
12 | 2640000001 |
13 | 12cb1cbbb1 |
14 | 8ba303041 |
15 | 5150a1cad |
hex | 309690001 |
13042778113 has 4 divisors (see below), whose sum is σ = 13118170068. Its totient is φ = 12967386160.
The previous prime is 13042778071. The next prime is 13042778137. The reversal of 13042778113 is 31187724031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12024657649 + 1018120464 = 109657^2 + 31908^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13042778113 is a prime.
It is a super-2 number, since 2×130427781132 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13042728113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37695718 + ... + 37696063.
It is an arithmetic number, because the mean of its divisors is an integer number (3279542517).
Almost surely, 213042778113 is an apocalyptic number.
It is an amenable number.
13042778113 is a deficient number, since it is larger than the sum of its proper divisors (75391955).
13042778113 is an equidigital number, since it uses as much as digits as its factorization.
13042778113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75391954.
The product of its (nonzero) digits is 28224, while the sum is 37.
The spelling of 13042778113 in words is "thirteen billion, forty-two million, seven hundred seventy-eight thousand, one hundred thirteen".
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