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1304314401255 = 35312804977207
BaseRepresentation
bin10010111110101111001…
…100100101000111100111
311121200122220122202010020
4102332233030211013213
5132332213441320010
62435105504130223
7163143061324605
oct22765714450747
94550586582106
101304314401255
1146317a526768
12190950306973
1395cc4bb98a8
14471b4580875
1523ddcaa1470
hex12faf3251e7

1304314401255 has 16 divisors (see below), whose sum is σ = 2154222495744. Its totient is φ = 673194529440.

The previous prime is 1304314401217. The next prime is 1304314401259. The reversal of 1304314401255 is 5521044134031.

It is not a de Polignac number, because 1304314401255 - 28 = 1304314400999 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304314401259) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1402488139 + ... + 1402489068.

It is an arithmetic number, because the mean of its divisors is an integer number (134638905984).

Almost surely, 21304314401255 is an apocalyptic number.

1304314401255 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1304314401255 is a deficient number, since it is larger than the sum of its proper divisors (849908094489).

1304314401255 is a wasteful number, since it uses less digits than its factorization.

1304314401255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2804977246.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 1304314401255 its reverse (5521044134031), we get a palindrome (6825358535286).

The spelling of 1304314401255 in words is "one trillion, three hundred four billion, three hundred fourteen million, four hundred one thousand, two hundred fifty-five".

Divisors: 1 3 5 15 31 93 155 465 2804977207 8414931621 14024886035 42074658105 86954293417 260862880251 434771467085 1304314401255