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1304324103121 = 131032513880889
BaseRepresentation
bin10010111110101111110…
…001100101101111010001
311121200200120220122120121
4102332233301211233101
5132332223432244441
62435110452110241
7163143236643124
oct22765761455721
94550616818517
101304324103121
11463184a52936
12190953605381
1395cc6c05840
14471b59883bb
1523ddd86add1
hex12fafc65bd1

1304324103121 has 16 divisors (see below), whose sum is σ = 1423945111680. Its totient is φ = 1187551728000.

The previous prime is 1304324103113. The next prime is 1304324103127. The reversal of 1304324103121 is 1213014234031.

It is a cyclic number.

It is not a de Polignac number, because 1304324103121 - 23 = 1304324103113 is a prime.

It is a super-2 number, since 2×13043241031212 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1304324103127) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1604356 + ... + 2276533.

It is an arithmetic number, because the mean of its divisors is an integer number (88996569480).

Almost surely, 21304324103121 is an apocalyptic number.

It is an amenable number.

1304324103121 is a deficient number, since it is larger than the sum of its proper divisors (119621008559).

1304324103121 is a wasteful number, since it uses less digits than its factorization.

1304324103121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3881256.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1304324103121 its reverse (1213014234031), we get a palindrome (2517338337152).

The spelling of 1304324103121 in words is "one trillion, three hundred four billion, three hundred twenty-four million, one hundred three thousand, one hundred twenty-one".

Divisors: 1 13 103 251 1339 3263 25853 336089 3880889 50451557 399731567 974103139 5196510371 12663340807 100332623317 1304324103121