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13043242150400 = 2952711234313381
BaseRepresentation
bin1011110111001101110111…
…0100001010101000000000
31201011220212222020101000102
42331303131310022220000
53202200024442303100
643423552133541532
72514225461664620
oct275633564125000
951156788211012
1013043242150400
114179676180380
121567a4b4a48a8
13737c84646a67
14331421030880
15179440ae5cd5
hexbdcddd0aa00

13043242150400 has 960 divisors, whose sum is σ = 43022288111616. Its totient is φ = 3797950464000.

The previous prime is 13043242150363. The next prime is 13043242150409. The reversal of 13043242150400 is 405124234031.

It is not an unprimeable number, because it can be changed into a prime (13043242150409) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 974751710 + ... + 974765090.

Almost surely, 213043242150400 is an apocalyptic number.

13043242150400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13043242150400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21511144055808).

13043242150400 is an abundant number, since it is smaller than the sum of its proper divisors (29979045961216).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13043242150400 is a wasteful number, since it uses less digits than its factorization.

13043242150400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13493 (or 13472 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 13043242150400 its reverse (405124234031), we get a palindrome (13448366384431).

The spelling of 13043242150400 in words is "thirteen trillion, forty-three billion, two hundred forty-two million, one hundred fifty thousand, four hundred".