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1304331231155 = 5318415040201
BaseRepresentation
bin10010111110110000001…
…100110001111110110011
311121200201002022210101212
4102332300030301332303
5132332232243344110
62435111304550335
7163143354351431
oct22766014617663
94550632283355
101304331231155
11463188a81277
12190955a823ab
1395cc8530104
14471b68c1d51
1523dde2c7e05
hex12fb0331fb3

1304331231155 has 8 divisors (see below), whose sum is σ = 1615687718784. Its totient is φ = 1009804824000.

The previous prime is 1304331231149. The next prime is 1304331231191. The reversal of 1304331231155 is 5511321334031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1304331231155 - 210 = 1304331230131 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4207519946 + ... + 4207520255.

It is an arithmetic number, because the mean of its divisors is an integer number (201960964848).

Almost surely, 21304331231155 is an apocalyptic number.

1304331231155 is a deficient number, since it is larger than the sum of its proper divisors (311356487629).

1304331231155 is an equidigital number, since it uses as much as digits as its factorization.

1304331231155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8415040237.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 1304331231155 its reverse (5511321334031), we get a palindrome (6815652565186).

The spelling of 1304331231155 in words is "one trillion, three hundred four billion, three hundred thirty-one million, two hundred thirty-one thousand, one hundred fifty-five".

Divisors: 1 5 31 155 8415040201 42075201005 260866246231 1304331231155