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13043312553 = 34347770851
BaseRepresentation
bin11000010010111000…
…10010011110101001
31020200000021221010010
430021130102132221
5203203042000203
65554135242133
7641140220205
oct141134223651
936600257103
1013043312553
115593678857
122640219349
1312cb35822b
148ba401b05
1551515a303
hex3097127a9

13043312553 has 4 divisors (see below), whose sum is σ = 17391083408. Its totient is φ = 8695541700.

The previous prime is 13043312551. The next prime is 13043312563. The reversal of 13043312553 is 35521334031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13043312553 - 21 = 13043312551 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13043312553.

It is not an unprimeable number, because it can be changed into a prime (13043312551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2173885423 + ... + 2173885428.

It is an arithmetic number, because the mean of its divisors is an integer number (4347770852).

Almost surely, 213043312553 is an apocalyptic number.

It is an amenable number.

13043312553 is a deficient number, since it is larger than the sum of its proper divisors (4347770855).

13043312553 is an equidigital number, since it uses as much as digits as its factorization.

13043312553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4347770854.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 13043312553 its reverse (35521334031), we get a palindrome (48564646584).

The spelling of 13043312553 in words is "thirteen billion, forty-three million, three hundred twelve thousand, five hundred fifty-three".

Divisors: 1 3 4347770851 13043312553