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130433212113 = 3173769121999
BaseRepresentation
bin111100101111001101…
…1001101111011010001
3110110200010002200220220
41321132123031323101
54114111400241423
6135530432223253
712265154003301
oct1713633157321
9413603080826
10130433212113
1150353169876
122134199ab29
13c3b8874169
146454c37601
1535d5dd79e3
hex1e5e6cded1

130433212113 has 16 divisors (see below), whose sum is σ = 189117792000. Its totient is φ = 79628541696.

The previous prime is 130433212099. The next prime is 130433212121. The reversal of 130433212113 is 311212334031.

It is not a de Polignac number, because 130433212113 - 213 = 130433203921 is a prime.

It is a super-2 number, since 2×1304332121132 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (130433212193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34559113 + ... + 34562886.

It is an arithmetic number, because the mean of its divisors is an integer number (11819862000).

Almost surely, 2130433212113 is an apocalyptic number.

It is an amenable number.

130433212113 is a deficient number, since it is larger than the sum of its proper divisors (58684579887).

130433212113 is a wasteful number, since it uses less digits than its factorization.

130433212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69122056.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 130433212113 its reverse (311212334031), we get a palindrome (441645546144).

The spelling of 130433212113 in words is "one hundred thirty billion, four hundred thirty-three million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 17 37 51 111 629 1887 69121999 207365997 1175073983 2557513963 3525221949 7672541889 43477737371 130433212113