130440000310421 has 4 divisors (see below), whose sum is σ = 130444377080832. Its totient is φ = 130435623540012.

The previous prime is 130440000310409. The next prime is 130440000310439. The reversal of 130440000310421 is 124013000044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130440000310421 - 2²² = 130439996116117 is a prime.

It is a super-2 number, since 2×130440000310421² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130440000310621) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2188340501 + ... + 2188400106.

It is an arithmetic number, because the mean of its divisors is an integer number (32611094270208).

Almost surely, 2^{130440000310421} is an apocalyptic number.

It is an amenable number.

130440000310421 is a deficient number, since it is larger than the sum of its proper divisors (4376770411).

130440000310421 is an equidigital number, since it uses as much as digits as its factorization.

130440000310421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4376770410.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 130440000310421 its reverse (124013000044031), we get a palindrome (254453000354452).

The spelling of 130440000310421 in words is "one hundred thirty trillion, four hundred forty billion, three hundred ten thousand, four hundred twenty-one".