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130440000323403 = 341610370374363
BaseRepresentation
bin11101101010001001101101…
…111000100011111101001011
3122002211221102220020121220000
4131222021231320203331023
5114044112110040322103
61141231150415534043
736321656543561241
oct3552115570437513
9562757386217800
10130440000323403
1138620325689641
121276819022a323
1357a259305a034
14242d4889b4791
15101309c9deaa3
hex76a26de23f4b

130440000323403 has 10 divisors (see below), whose sum is σ = 194854815298044. Its totient is φ = 86960000215548.

The previous prime is 130440000323393. The next prime is 130440000323407. The reversal of 130440000323403 is 304323000044031.

It is not a de Polignac number, because 130440000323403 - 24 = 130440000323387 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (130440000323407) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 805185187101 + ... + 805185187262.

Almost surely, 2130440000323403 is an apocalyptic number.

130440000323403 is a deficient number, since it is larger than the sum of its proper divisors (64414814974641).

130440000323403 is an equidigital number, since it uses as much as digits as its factorization.

130440000323403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1610370374375 (or 1610370374366 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 27.

Adding to 130440000323403 its reverse (304323000044031), we get a palindrome (434763000367434).

The spelling of 130440000323403 in words is "one hundred thirty trillion, four hundred forty billion, three hundred twenty-three thousand, four hundred three".

Divisors: 1 3 9 27 81 1610370374363 4831111123089 14493333369267 43480000107801 130440000323403