Base | Representation |
---|---|
bin | 1011110111010000101100… |
… | …0011011010011111000001 |
3 | 1201011222211212101010122121 |
4 | 2331310023003122133001 |
5 | 3202203103241402431 |
6 | 43424155325204241 |
7 | 2514253336101535 |
oct | 275641303323701 |
9 | 51158755333577 |
10 | 13044001122241 |
11 | 4179a25639131 |
12 | 1568021700681 |
13 | 73807596311b |
14 | 331493b59bc5 |
15 | 179487566611 |
hex | bdd0b0da7c1 |
13044001122241 has 8 divisors (see below), whose sum is σ = 13216454657280. Its totient is φ = 12871911799152.
The previous prime is 13044001122223. The next prime is 13044001122253. The reversal of 13044001122241 is 14222110044031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13044001122241 - 25 = 13044001122209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13044001122221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 90980886 + ... + 91124143.
It is an arithmetic number, because the mean of its divisors is an integer number (1652056832160).
Almost surely, 213044001122241 is an apocalyptic number.
It is an amenable number.
13044001122241 is a deficient number, since it is larger than the sum of its proper divisors (172453535039).
13044001122241 is an equidigital number, since it uses as much as digits as its factorization.
13044001122241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 182105975.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13044001122241 its reverse (14222110044031), we get a palindrome (27266111166272).
The spelling of 13044001122241 in words is "thirteen trillion, forty-four billion, one million, one hundred twenty-two thousand, two hundred forty-one".
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