1304400403 has 4 divisors (see below), whose sum is σ = 1361113488. Its totient is φ = 1247687320.

The previous prime is 1304400401. The next prime is 1304400439. The reversal of 1304400403 is 3040044031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3040044031 = 24877 ⋅122203.

It is a cyclic number.

It is not a de Polignac number, because 1304400403 - 2¹ = 1304400401 is a prime.

It is a super-2 number, since 2×1304400403² = 3402920822693124818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1304400401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28356508 + ... + 28356553.

It is an arithmetic number, because the mean of its divisors is an integer number (340278372).

Almost surely, 2^1304400403 is an apocalyptic number.

1304400403 is a deficient number, since it is larger than the sum of its proper divisors (56713085).

1304400403 is an equidigital number, since it uses as much as digits as its factorization.

1304400403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56713084.

The product of its (nonzero) digits is 576, while the sum is 19.

The square root of 1304400403 is about 36116.4838127966. The cubic root of 1304400403 is about 1092.6229240625.

Adding to 1304400403 its reverse (3040044031), we get a palindrome (4344444434).

The spelling of 1304400403 in words is "one billion, three hundred four million, four hundred thousand, four hundred three".