Base | Representation |
---|---|
bin | 100110110111111… |
… | …1001001000010001 |
3 | 10100220110101221222 |
4 | 1031233321020101 |
5 | 10132411303101 |
6 | 333233454425 |
7 | 44216135423 |
oct | 11557711021 |
9 | 3326411858 |
10 | 1304400401 |
11 | 60a333367 |
12 | 304a11415 |
13 | 17a318b75 |
14 | c5348813 |
15 | 797ae01b |
hex | 4dbf9211 |
1304400401 has 2 divisors, whose sum is σ = 1304400402. Its totient is φ = 1304400400.
The previous prime is 1304400397. The next prime is 1304400439. The reversal of 1304400401 is 1040044031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1221153025 + 83247376 = 34945^2 + 9124^2 .
It is a cyclic number.
It is not a de Polignac number, because 1304400401 - 22 = 1304400397 is a prime.
It is a super-2 number, since 2×13044004012 = 3402920812257921602, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1304400401.
It is not a weakly prime, because it can be changed into another prime (1304400301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 652200200 + 652200201.
It is an arithmetic number, because the mean of its divisors is an integer number (652200201).
Almost surely, 21304400401 is an apocalyptic number.
It is an amenable number.
1304400401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1304400401 is an equidigital number, since it uses as much as digits as its factorization.
1304400401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 17.
The square root of 1304400401 is about 36116.4837851084. The cubic root of 1304400401 is about 1092.6229235040.
Adding to 1304400401 its reverse (1040044031), we get a palindrome (2344444432).
The spelling of 1304400401 in words is "one billion, three hundred four million, four hundred thousand, four hundred one".
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