13044013230343 has 4 divisors (see below), whose sum is σ = 13493806790040. Its totient is φ = 12594219670648.

The previous prime is 13044013230341. The next prime is 13044013230371. The reversal of 13044013230343 is 34303231044031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13044013230343 - 2¹ = 13044013230341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13044013230341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 224896779805 + ... + 224896779862.

It is an arithmetic number, because the mean of its divisors is an integer number (3373451697510).

Almost surely, 2^{13044013230343} is an apocalyptic number.

13044013230343 is a deficient number, since it is larger than the sum of its proper divisors (449793559697).

13044013230343 is an equidigital number, since it uses as much as digits as its factorization.

13044013230343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 449793559696.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 13044013230343 its reverse (34303231044031), we get a palindrome (47347244274374).

The spelling of 13044013230343 in words is "thirteen trillion, forty-four billion, thirteen million, two hundred thirty thousand, three hundred forty-three".