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130440223444442 = 265220111722221
BaseRepresentation
bin11101101010001001111011…
…001011101100110111011010
3122002211222000110002100102012
4131222021323023230313122
5114044113034200210232
61141231224510105522
736321665223224012
oct3552117313546732
9562758013070365
10130440223444442
113862042a62379a
1212768232aab2a2
1357a25ca34b212
14242d4aa494c42
1510130b23b49b2
hex76a27b2ecdda

130440223444442 has 4 divisors (see below), whose sum is σ = 195660335166666. Its totient is φ = 65220111722220.

The previous prime is 130440223444409. The next prime is 130440223444457. The reversal of 130440223444442 is 244444322044031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 113678478564121 + 16761744880321 = 10662011^2 + 4094111^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 130440223444442.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32610055861109 + ... + 32610055861112.

Almost surely, 2130440223444442 is an apocalyptic number.

130440223444442 is a deficient number, since it is larger than the sum of its proper divisors (65220111722224).

130440223444442 is an equidigital number, since it uses as much as digits as its factorization.

130440223444442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65220111722223.

The product of its (nonzero) digits is 1179648, while the sum is 41.

Adding to 130440223444442 its reverse (244444322044031), we get a palindrome (374884545488473).

The spelling of 130440223444442 in words is "one hundred thirty trillion, four hundred forty billion, two hundred twenty-three million, four hundred forty-four thousand, four hundred forty-two".

Divisors: 1 2 65220111722221 130440223444442