Base | Representation |
---|---|
bin | 1011110111010000110001… |
… | …0100101101001001010101 |
3 | 1201011222220100110210121120 |
4 | 2331310030110231021111 |
5 | 3202203124220313331 |
6 | 43424201410034153 |
7 | 2514254015165235 |
oct | 275641424551125 |
9 | 51158810423546 |
10 | 13044022432341 |
11 | 4179a3667378a |
12 | 1568028878959 |
13 | 73807a1b4954 |
14 | 331496905cc5 |
15 | 179489375796 |
hex | bdd0c52d255 |
13044022432341 has 8 divisors (see below), whose sum is σ = 18307399905120. Its totient is φ = 8238329957232.
The previous prime is 13044022432339. The next prime is 13044022432361. The reversal of 13044022432341 is 14323422044031.
13044022432341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13044022432341 - 21 = 13044022432339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044022432361) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 114421249350 + ... + 114421249463.
It is an arithmetic number, because the mean of its divisors is an integer number (2288424988140).
Almost surely, 213044022432341 is an apocalyptic number.
It is an amenable number.
13044022432341 is a deficient number, since it is larger than the sum of its proper divisors (5263377472779).
13044022432341 is a wasteful number, since it uses less digits than its factorization.
13044022432341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 228842498835.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 13044022432341 its reverse (14323422044031), we get a palindrome (27367444476372).
The spelling of 13044022432341 in words is "thirteen trillion, forty-four billion, twenty-two million, four hundred thirty-two thousand, three hundred forty-one".
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