Base | Representation |
---|---|
bin | 11101101010001001111100… |
… | …001110101101011100001011 |
3 | 122002211222001200010210102211 |
4 | 131222021330032231130023 |
5 | 114044113103144313233 |
6 | 1141231230334405551 |
7 | 36321665525434600 |
oct | 3552117416553413 |
9 | 562758050123384 |
10 | 130440241010443 |
11 | 38620439531351 |
12 | 127682389608b7 |
13 | 57a2600b8b7c0 |
14 | 242d4ac9486a7 |
15 | 10130b3bd45cd |
hex | 76a27c3ad70b |
130440241010443 has 48 divisors (see below), whose sum is σ = 170523146445120. Its totient is φ = 98712615665664.
The previous prime is 130440241010353. The next prime is 130440241010447. The reversal of 130440241010443 is 344010142044031.
It is not a de Polignac number, because 130440241010443 - 241 = 128241217754891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (130440241010447) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 264893163 + ... + 265385131.
It is an arithmetic number, because the mean of its divisors is an integer number (3552565550940).
Almost surely, 2130440241010443 is an apocalyptic number.
130440241010443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
130440241010443 is a deficient number, since it is larger than the sum of its proper divisors (40082905434677).
130440241010443 is a wasteful number, since it uses less digits than its factorization.
130440241010443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 510116 (or 510109 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 130440241010443 its reverse (344010142044031), we get a palindrome (474450383054474).
The spelling of 130440241010443 in words is "one hundred thirty trillion, four hundred forty billion, two hundred forty-one million, ten thousand, four hundred forty-three".
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