Base | Representation |
---|---|
bin | 11101101010001001111100… |
… | …001110110000100000010111 |
3 | 122002211222001200011102122212 |
4 | 131222021330032300200113 |
5 | 114044113103200213444 |
6 | 1141231230334544035 |
7 | 36321665525516315 |
oct | 3552117416604027 |
9 | 562758050142585 |
10 | 130440241022999 |
11 | 3862043953a826 |
12 | 1276823896801b |
13 | 57a2600b9442b |
14 | 242d4ac94d0b5 |
15 | 10130b3bd819e |
hex | 76a27c3b0817 |
130440241022999 has 4 divisors (see below), whose sum is σ = 130440264815664. Its totient is φ = 130440217230336.
The previous prime is 130440241022977. The next prime is 130440241023041. The reversal of 130440241022999 is 999220142044031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 130440241022999 - 212 = 130440241018903 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130440211022999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 954614 + ... + 16179980.
It is an arithmetic number, because the mean of its divisors is an integer number (32610066203916).
Almost surely, 2130440241022999 is an apocalyptic number.
130440241022999 is a deficient number, since it is larger than the sum of its proper divisors (23792665).
130440241022999 is an equidigital number, since it uses as much as digits as its factorization.
130440241022999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23792664.
The product of its (nonzero) digits is 1119744, while the sum is 50.
The spelling of 130440241022999 in words is "one hundred thirty trillion, four hundred forty billion, two hundred forty-one million, twenty-two thousand, nine hundred ninety-nine".
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