Base | Representation |
---|---|
bin | 1011110111010000110011… |
… | …0010010110100010000011 |
3 | 1201011222220220002122101002 |
4 | 2331310030302112202003 |
5 | 3202203133213012120 |
6 | 43424202244402215 |
7 | 2514254141224235 |
oct | 275641462264203 |
9 | 51158826078332 |
10 | 13044030204035 |
11 | 4179a3aaa1776 |
12 | 156802b3a636b |
13 | 73807b9a619c |
14 | 33149796a255 |
15 | 179489dad375 |
hex | bdd0cc96883 |
13044030204035 has 16 divisors (see below), whose sum is σ = 16575641603136. Its totient is φ = 9820172464128.
The previous prime is 13044030203999. The next prime is 13044030204061. The reversal of 13044030204035 is 53040203044031.
It is a cyclic number.
It is not a de Polignac number, because 13044030204035 - 222 = 13044026009731 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13044030203989 and 13044030204007.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8800622 + ... + 10175411.
It is an arithmetic number, because the mean of its divisors is an integer number (1035977600196).
Almost surely, 213044030204035 is an apocalyptic number.
13044030204035 is a deficient number, since it is larger than the sum of its proper divisors (3531611399101).
13044030204035 is a wasteful number, since it uses less digits than its factorization.
13044030204035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18984142.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 13044030204035 its reverse (53040203044031), we get a palindrome (66084233248066).
The spelling of 13044030204035 in words is "thirteen trillion, forty-four billion, thirty million, two hundred four thousand, thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •