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13044030204034 = 26522015102017
BaseRepresentation
bin1011110111010000110011…
…0010010110100010000010
31201011222220220002122101001
42331310030302112202002
53202203133213012114
643424202244402214
72514254141224234
oct275641462264202
951158826078331
1013044030204034
114179a3aaa1775
12156802b3a636a
1373807b9a619b
1433149796a254
15179489dad374
hexbdd0cc96882

13044030204034 has 4 divisors (see below), whose sum is σ = 19566045306054. Its totient is φ = 6522015102016.

The previous prime is 13044030203999. The next prime is 13044030204061. The reversal of 13044030204034 is 43040203044031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 8152435431009 + 4891594773025 = 2855247^2 + 2211695^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13044030203993 and 13044030204011.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3261007551007 + ... + 3261007551010.

Almost surely, 213044030204034 is an apocalyptic number.

13044030204034 is a deficient number, since it is larger than the sum of its proper divisors (6522015102020).

13044030204034 is an equidigital number, since it uses as much as digits as its factorization.

13044030204034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6522015102019.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 13044030204034 its reverse (43040203044031), we get a palindrome (56084233248065).

The spelling of 13044030204034 in words is "thirteen trillion, forty-four billion, thirty million, two hundred four thousand, thirty-four".

Divisors: 1 2 6522015102017 13044030204034