Base | Representation |
---|---|
bin | 11000010010111110… |
… | …00100001000100111 |
3 | 1020200001122220022011 |
4 | 30021133010020213 |
5 | 203203233241411 |
6 | 5554203015051 |
7 | 641146340545 |
oct | 141137041047 |
9 | 36601586264 |
10 | 13044040231 |
11 | 5594025542 |
12 | 264050a487 |
13 | 12cb551501 |
14 | 8ba550d95 |
15 | 515250c21 |
hex | 3097c4227 |
13044040231 has 4 divisors (see below), whose sum is σ = 13050169200. Its totient is φ = 13037911264.
The previous prime is 13044040187. The next prime is 13044040241. The reversal of 13044040231 is 13204044031.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13204044031 = 44867 ⋅294293.
It is a cyclic number.
It is not a de Polignac number, because 13044040231 - 219 = 13043515943 is a prime.
It is a super-2 number, since 2×130440402312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13044040241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3061291 + ... + 3065548.
It is an arithmetic number, because the mean of its divisors is an integer number (3262542300).
Almost surely, 213044040231 is an apocalyptic number.
13044040231 is a deficient number, since it is larger than the sum of its proper divisors (6128969).
13044040231 is an equidigital number, since it uses as much as digits as its factorization.
13044040231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6128968.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 13044040231 its reverse (13204044031), we get a palindrome (26248084262).
The spelling of 13044040231 in words is "thirteen billion, forty-four million, forty thousand, two hundred thirty-one".
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