1304405054101 has 4 divisors (see below), whose sum is σ = 1326513614400. Its totient is φ = 1282296493804.

The previous prime is 1304405054093. The next prime is 1304405054111. The reversal of 1304405054101 is 1014505044031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1304405054101 - 2³ = 1304405054093 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1304405054101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1304405054111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11054280061 + ... + 11054280178.

It is an arithmetic number, because the mean of its divisors is an integer number (331628403600).

Almost surely, 2^{1304405054101} is an apocalyptic number.

It is an amenable number.

1304405054101 is a deficient number, since it is larger than the sum of its proper divisors (22108560299).

1304405054101 is an equidigital number, since it uses as much as digits as its factorization.

1304405054101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22108560298.

The product of its (nonzero) digits is 4800, while the sum is 28.

The spelling of 1304405054101 in words is "one trillion, three hundred four billion, four hundred five million, fifty-four thousand, one hundred one".