130441003000441 has 16 divisors (see below), whose sum is σ = 149166991946880. Its totient is φ = 111737920769280.

The previous prime is 130441003000433. The next prime is 130441003000459. The reversal of 130441003000441 is 144000300144031.

It is a cyclic number.

It is not a de Polignac number, because 130441003000441 - 2³ = 130441003000433 is a prime.

It is a super-2 number, since 2×130441003000441² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130441003004441) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93433345 + ... + 94819153.

It is an arithmetic number, because the mean of its divisors is an integer number (9322936996680).

Almost surely, 2^{130441003000441} is an apocalyptic number.

It is an amenable number.

130441003000441 is a deficient number, since it is larger than the sum of its proper divisors (18725988946439).

130441003000441 is a wasteful number, since it uses less digits than its factorization.

130441003000441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1394064.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 130441003000441 its reverse (144000300144031), we get a palindrome (274441303144472).

The spelling of 130441003000441 in words is "one hundred thirty trillion, four hundred forty-one billion, three million, four hundred forty-one", and thus it is an aban number.