130441044024433 has 8 divisors (see below), whose sum is σ = 133474841438400. Its totient is φ = 127407259554288.

The previous prime is 130441044024419. The next prime is 130441044024479. The reversal of 130441044024433 is 334420440144031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-130441044024433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130441044024392 and 130441044024401.

It is not an unprimeable number, because it can be changed into a prime (130441044024133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18892908 + ... + 24856066.

It is an arithmetic number, because the mean of its divisors is an integer number (16684355179800).

Almost surely, 2^{130441044024433} is an apocalyptic number.

It is an amenable number.

130441044024433 is a deficient number, since it is larger than the sum of its proper divisors (3033797413967).

130441044024433 is an equidigital number, since it uses as much as digits as its factorization.

130441044024433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6471911.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 130441044024433 its reverse (334420440144031), we get a palindrome (464861484168464).

The spelling of 130441044024433 in words is "one hundred thirty trillion, four hundred forty-one billion, forty-four million, twenty-four thousand, four hundred thirty-three".