13044140412041 has 4 divisors (see below), whose sum is σ = 13056031151892. Its totient is φ = 13032249672192.

The previous prime is 13044140412031. The next prime is 13044140412097. The reversal of 13044140412041 is 14021404144031.

It is a happy number.

13044140412041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2687071714441 + 10357068697600 = 1639229^2 + 3218240^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13044140412041 is a prime.

It is a super-2 number, since 2×13044140412041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13044140411995 and 13044140412013.

It is not an unprimeable number, because it can be changed into a prime (13044140412031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5945368280 + ... + 5945370473.

It is an arithmetic number, because the mean of its divisors is an integer number (3264007787973).

Almost surely, 2^{13044140412041} is an apocalyptic number.

It is an amenable number.

13044140412041 is a deficient number, since it is larger than the sum of its proper divisors (11890739851).

13044140412041 is a wasteful number, since it uses less digits than its factorization.

13044140412041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11890739850.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 13044140412041 its reverse (14021404144031), we get a palindrome (27065544556072).

The spelling of 13044140412041 in words is "thirteen trillion, forty-four billion, one hundred forty million, four hundred twelve thousand, forty-one".