Base | Representation |
---|---|
bin | 11000010010111110… |
… | …11101000010010001 |
3 | 1020200001212002012201 |
4 | 30021133131002101 |
5 | 203203300022400 |
6 | 5554205123201 |
7 | 641150244112 |
oct | 141137350221 |
9 | 36601762181 |
10 | 13044142225 |
11 | 5594095134 |
12 | 2640559501 |
13 | 12cb588a6a |
14 | 8ba57a209 |
15 | 51527106a |
hex | 3097dd091 |
13044142225 has 6 divisors (see below), whose sum is σ = 16174736390. Its totient is φ = 10435313760.
The previous prime is 13044142213. The next prime is 13044142253. The reversal of 13044142225 is 52224144031.
It can be written as a sum of positive squares in 3 ways, for example, as 57032704 + 12987109521 = 7552^2 + 113961^2 .
It is not a de Polignac number, because 13044142225 - 25 = 13044142193 is a prime.
It is a super-3 number, since 3×130441422253 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13044142193 and 13044142202.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 260882820 + ... + 260882869.
Almost surely, 213044142225 is an apocalyptic number.
It is an amenable number.
13044142225 is a deficient number, since it is larger than the sum of its proper divisors (3130594165).
13044142225 is an equidigital number, since it uses as much as digits as its factorization.
13044142225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 521765699 (or 521765694 counting only the distinct ones).
The product of its (nonzero) digits is 7680, while the sum is 28.
Adding to 13044142225 its reverse (52224144031), we get a palindrome (65268286256).
The spelling of 13044142225 in words is "thirteen billion, forty-four million, one hundred forty-two thousand, two hundred twenty-five".
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