Base | Representation |
---|---|
bin | 10010111110110101100… |
… | …000001011111110000111 |
3 | 11121200221021202002210002 |
4 | 102332311200023332013 |
5 | 132332423033020143 |
6 | 2435124203551515 |
7 | 163145514536630 |
oct | 22766540137607 |
9 | 4550837662702 |
10 | 1304420204423 |
11 | 4632242211a6 |
12 | 19097b82b59b |
13 | 96010ab290b |
14 | 471c4642887 |
15 | 23de70005b8 |
hex | 12fb580bf87 |
1304420204423 has 16 divisors (see below), whose sum is σ = 1496421276480. Its totient is φ = 1113839980800.
The previous prime is 1304420204393. The next prime is 1304420204443. The reversal of 1304420204423 is 3244020244031.
It is a cyclic number.
It is not a de Polignac number, because 1304420204423 - 214 = 1304420188039 is a prime.
It is a super-2 number, since 2×13044202044232 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304420204443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1943843 + ... + 2527323.
It is an arithmetic number, because the mean of its divisors is an integer number (93526329780).
Almost surely, 21304420204423 is an apocalyptic number.
1304420204423 is a deficient number, since it is larger than the sum of its proper divisors (192001072057).
1304420204423 is an equidigital number, since it uses as much as digits as its factorization.
1304420204423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 584698.
The product of its (nonzero) digits is 18432, while the sum is 29.
Adding to 1304420204423 its reverse (3244020244031), we get a palindrome (4548440448454).
The spelling of 1304420204423 in words is "one trillion, three hundred four billion, four hundred twenty million, two hundred four thousand, four hundred twenty-three".
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