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130442102340234 = 23135701160207739
BaseRepresentation
bin11101101010001011101011…
…001011000111101010001010
3122002212010212101120010220020
4131222023223023013222022
5114044130411144341414
61141232135145241310
736322062616455216
oct3552135313075212
9562763771503806
10130442102340234
1138621204174a33
1212768678193236
1357a28396a2b89
14242d607c27946
1510131723047a9
hex76a2eb2c7a8a

130442102340234 has 16 divisors (see below), whose sum is σ = 260886128801760. Its totient is φ = 43480380093200.

The previous prime is 130442102340227. The next prime is 130442102340247. The reversal of 130442102340234 is 432043201244031.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130442102340195 and 130442102340204.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 79289664 + ... + 80918075.

It is an arithmetic number, because the mean of its divisors is an integer number (16305383050110).

Almost surely, 2130442102340234 is an apocalyptic number.

130442102340234 is an abundant number, since it is smaller than the sum of its proper divisors (130444026461526).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130442102340234 is a wasteful number, since it uses less digits than its factorization.

130442102340234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160343445.

The product of its (nonzero) digits is 55296, while the sum is 33.

Adding to 130442102340234 its reverse (432043201244031), we get a palindrome (562485303584265).

The spelling of 130442102340234 in words is "one hundred thirty trillion, four hundred forty-two billion, one hundred two million, three hundred forty thousand, two hundred thirty-four".

Divisors: 1 2 3 6 135701 271402 407103 814206 160207739 320415478 480623217 961246434 21740350390039 43480700780078 65221051170117 130442102340234